 RESTful API: introduced in version 2013. New in AutoCAD 2014, this JSON based service uses HTTP to provide updates to the software. The API is also used to connect to AutoCAD from third party applications. Web Services: XML and JSON based services available in 2014. Web services are a Web-based, computer-to-computer, application-programming interface (API) which use HTTP to send and receive data. Miscellaneous software The following software are typically found in AutoCAD installations: References External links AutoCAD Autodesk Exchange Apps AutoCAD Community 3D Warehouse Autodesk Design Review for architects Web Services API AutoCAD Blog AutoCAD Wiki Category:Construction engineering software Category:3D graphics software Category:Computer-aided design software for Windows Category:Computer-aided design software for Linux Category:Computer-aided design software for macOS Category:Computer-aided design software for iOS Category:Computer-aided design software for Android Category:2007 software Category:Dimensional analysisQ: Quiz about an algebra problem The below problem is from my friend’s assessment. (I just typed it in to MathJax, and am not very good at typesetting equations.) Let $f,g:S^1 \to S^1$ be two orientation preserving piecewise linear maps. Let $x_0 \in S^1$ be a point of self-intersection of $f$ and $g$, and suppose that $f(x_0) = g(x_0)$. Prove that $f(x_0) = g(x_0)$ implies $f \circ g \circ f^{ -1} \circ g^{ -1}(x_0) = x_0$. In essence, it says that $f$ and $g$ cannot have common fixed points in $S^1$. My attempt: $f$ and $g$ are orientation preserving piecewise linear maps with no self-intersection. Since $f(x_0) = g(x_0)$, I know that $f(x_0) = g(x_0)$ implies $f \circ g(x_0) = g \circ f(x_0)$. 3813325f96